Re: (pi^4+pi^5)^(1/6)=e???

From: raymond manzoni (raymond.manzoni_at_wanadoo.fr)
Date: 07/20/04 

Date: Tue, 20 Jul 2004 17:13:55 +0200

The Last Danish Pastry wrote:

>
> Hmmm... "pi^(-13)" looks, to me, like an appeal to higher powers.
>
> Anyway, my entry is
>
> e = 1/(3/pi^6+9/6427)-pi^2+pi^4-pi^5
>
> with 11 correct digits.
>
> That "6427" really requires some explanation.
> Sadly, none is available.
>

   I have something too but can't get the number of correct digits!
   (:-) Ok it was cheating! :-( )

         e = (-1)^(-i/pi)

         Raymond