Re: How to calculate a useful size for a given pool
From: Brian Evans (b..evans_at_sympatico.ca)
Date: 08/02/04
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Date: Mon, 2 Aug 2004 15:44:27 -0400
"Gareth Williams" <gareth@nospam.com> wrote in message
news:pan.2004.08.02.11.50.20.547414@nospam.com...
> Scenario:
>
> 1. A firm receives 100,000 orders per week as electronic documents.
>
> 2. All documents are archived on CDROM.
>
> 3. A percentage of orders (average around 10%) will go wrong at some
> stage and access to the original order will be required by Customer
> Services to resolve the problem.
>
> 4. Retrieval from CDROM is time-consuming but a limited amount of space is
> available to cache some of the documents on networked storage for more
> immediate retrieval. There is not enough space to cache all the documents
> so the older cached documents are deleted regularly.
>
> 5. It is not possible to determine "up front" which orders will fail -
> whilst the failure rate is fairly constant over time, just about any
> document could end up being requested by Customer Services.
>
> Problem:
>
> The firm would like to cache "N" documents (from the weekly pool of
> 100,000 orders) such that they can satisfy "X" percent of Customer Service
> requests from the networked storage. Customer Services are prepared to
> put up with [100-X]% of requests that would still need to be retrieved
> from the CDROM store.
>
> In short, how do we calculate "N"?
>
> This reminds me a little of the "Cookie Jar" or "Sock Drawer" problem,
> but it bugs me that I can't puzzle it out. I'm not a hard-core
> statistician and would be grateful for any help. This is a genuine (i.e.
> non-homework) request, by the way. I've posted to other NGs with no luck
> so far.
#4 mostly likely doesn't hold true anymore.
Hardrives have increased in capacity making caching all the data easy. A
single 250gb drive caches 384 CDs worth at 650mb per CD. A fully
decked out $10,999 Apple XServe RAID would cache 5384 CDs.
Thats 35/mb of electronic documents per order if 100,000 are
stored on the XServer at any one time.
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