Re: Help, need to come up with simple equation

From: Raymond Manzoni (raymond.manzoni_at_wanadoo.fr)
Date: 08/21/04


Date: Sun, 22 Aug 2004 01:00:00 +0200

Mike wrote:
...
> num#1(answer) has to increase by a factor, the smaller num#2 gets
>
> eg.
> 1 = 25
> | |
> 100 = 1
>
> In any equation, if one number goes down so will the other, naturally.
> I need the opposite to happen, and my brain ain't coming up with
> anything hehe. I bet it's something ebarrasingly simple, but
> nevertheless I need help ^^.

   Proposition : inverse num#1 and proceed as usual!
    (or inverse num#2...)

   1/1 -> 25
    | |
   1/100 -> 1

   That is instead of y= a*x+b we need y= a/x+b

   here a/1 +b = 25
   and a/100 +b = 1
   subtracting both one gets :
           a(1-1/100)= 25-1 or a= 24*100/99= 800/33
           b= 25-a= (825-800)/33= 25/33

   your function is f(x)= (800/x+25)/33

   Exercise : replace 100 by n and 25 by m and find the general formula!

   Hoping it was clear,
                      Raymond



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