Re: Basic argument, algebraic integers

From: Rupert (rupertmccallum_at_yahoo.com)
Date: 10/03/04 

Date: 3 Oct 2004 16:04:20 -0700

jstevh@msn.com (James Harris) wrote in message news:<3c65f87.0410030904.402a133f@posting.google.com>...
<snip>

> so, dividing P(m) by f^2 gives
>
> P(m)/f^2 = (a_1 x/f + u)(a_2 x/f + u)(a_3 x + uf).
>

But there's no reason why a_1/f and a_2/f should be algebraic integers.

[rest deleted]

Quantcast