Re: Dumb arguments, and social stuff

From: James Harris (jstevh_at_msn.com)
Date: 10/15/04 

Date: 15 Oct 2004 16:36:29 -0700

Tim Smith <reply_in_group@mouse-potato.com> wrote in message news:<EGKbd.4739$SZ5.1620@newsread2.news.atl.earthlink.net>...
> In article <3c65f87.0410141641.626cb42@posting.google.com>, James Harris wrote:
> >> > I've answered it already. To recap, his argument assumes that if you can
> >> > prove that you don't have units in the ring of algebraic integers then you
> >> > refute my own argument.
> >>
> >> Wrong. How he *found* his counterexample to your "theorem" might have
> >> involved "units in the right of algebraic integers", but that is totally
> >> irrelevant to the existance of the counterexample.
> >>
> >
> > There is no counterexample. That's my point.
>
> Your "paper" states:
>
> Therefore, with the factorization
> 65x^3 - 12x + 1 = (a_1x + 1)(a_2x + 1)(a_3x + 1)
> one of the a's is coprime to 5.
>
> He shows that 8a^2+4a-45 divides both a and 5, where a is any of your a_1,
> a_2, or a_3. That's a counterexample to the claim that one of the a's is
> coprime to 5.

You're a troll. The a's are algebraic integers.

James Harris

Relevant Pages

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