Roots of x^3 = 1;
From: Saju (saju.pillai_at_gmail.com)
Date: 10/27/04
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Date: 26 Oct 2004 21:53:15 -0700
Hello,
I was teaching myself some algebra when I got stuck at the following
...
I am trying to find roots of x^3 = 1
x =1 is a solution. But keeping x = i^(4/3) also seems to work, so
does i^(8/3), i^(16/3) and so on - I am able to generate 1 real root
and infinite complex roots - this must be bogus.
According to the theory, x^3 = 1 must have 3 roots (real+complex) - so
what am I missing ?
regards
srp
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