Re: Generalized Eigenvalue Problem for Three matrices
From: Robert Israel (israel_at_math.ubc.ca)
Date: 10/31/04
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Date: 31 Oct 2004 07:50:14 GMT
In article <d93ed69a.0410300902.15980e0d@posting.google.com>,
Sameer Agarwal <sandwichmaker@gmail.com> wrote:
>In my work I have encountered a problem of the following form
>(A - \lambda B - \mu C) x = 0
>where x is an unknown 3x1 vector and A,B,C are nx3 matrices. The
>scalars \mu and \lambda are also unknown.
You want lambda and mu so that A - lambda B - mu C has rank
< 3. Now this is equivalent to saying that every 3 x 3 submatrix
has determinant 0. For any choice of the three rows,
the determinant of this submatrix is a polynomial in lambda and mu.
In the easy case, two of these polynomials will have a nonzero
resultant with respect to one of the variables, and then you have
a finite number of possibilities to check. In general, I think
you can use Groebner basis methods to find the solutions.
Robert Israel israel@math.ubc.ca
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
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