Re: what priority does convolution "*" have? The same as multiplication?(dot?)

From: Jerry Avins (jya_at_ieee.org)
Date: 11/12/04 

Date: Fri, 12 Nov 2004 11:34:15 -0500

G. A. Edgar wrote:

> In article <10p9gpemtk5l47b@corp.supernews.com>, Ken Prager
> <prager_me_@ieee.org> wrote:
>
>
>>ie., is the following true...
>>
>>f(t)[g(t) * h(t)] = [f(t)g(t)] * h(t)
>>
>>If you write it out in terms of integrals (or sums for the discrete time
>>case), you will see that it is true.
>>
>>Ken P.
>>
>
>
> ???
>
> No. Try f = g = h where f(x)=1 on [0,1] and = 0 elsewhere.
> Then f[g*h] is zero on (1,2) but [fg]*h isn't.

A condition is that the signal is bandlimited. Your signal isn't.

Jerry 

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