Re: Cantor's diagonal proof wrong?
From: Virgil (ITSnetNOTcom#virgil_at_COMCAST.com)
Date: 11/14/04
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Date: Sun, 14 Nov 2004 14:13:43 -0700
In article <20041114140504.885$0X@newsreader.com>,
curt@kcwc.com (Curt Welch) wrote:
> Torkel Franzen <torkel@sm.luth.se> wrote:
> > curt@kcwc.com (Curt Welch) writes:
> >
> > > How can you show my
> > > argument is invalid and at the same time, keep Cantor's logic about the
> > > relationship between the integers and reals as valid?
> >
> > If you're a genuine crank, it is of course quite impossible to show
> > you anything. If you're not, you'll find out about these things for
> > yourself.
>
> So far, everyone has taken issue with my defintion of "reals" or with the
> idea that my mapping from reals to integers is not complete. And that's
> fine. It is not easy for me to argue my position there because I don't
> have the correct foundation.
>
> But how can you show me (ok, a student of your's who is not a crank), where
> the flaw is in the logic I used to show that the table of integers does not
> contain all the integers?
The "contradiction" is that you cannot prove that *every* table of
integers is missing some integers whereas Cantor has proved that *every*
table of reals is missing some reals (in fact missing more than are
actually tabulated).
>
> It's clear from the defintion of the table, that it does contain all the
> integers. Yet, when we apply the same logic which Cantor's proof used, we
> are able to contruct an integer which is not in the table.
>
> Is your position that the integer we construct is not an integer? So
> therefor it's not surprising that it is missing from the table?
>
> Ah, I think that argument would fit into the arguments I've seen put forth
> in this thead so far. If that is the position, then I see I won't be able
> to stop here. I'll have to go deeper. I'll have to find a way to show the
> contradiction exists in some set of axioms. Damn.
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