Re: JSH: Operator ambiguity, Escultura
From: George Cox (george_coxanti_at_spambtinternet.com.invalid)
Date: 11/28/04
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Date: Sun, 28 Nov 2004 17:16:05 +0000 (UTC)
James Harris wrote:
>
> ...
> of the square root but as Escultura showed, that doesn't work:
>
> i = sqrt(-1) = sqrt(1/-1) = 1/i, giving -1 = 1. Contradiction.
You, or Escultura, whomever, thereby proves that
sqrt(x/y) != sqrt(x)/sqrt(y)
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