Re: Help soving this problem?
From: darrenn (naylod-nospam_at_juno.com)
Date: 12/02/04
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Date: Wed, 1 Dec 2004 20:29:48 -0800
So each point must solve the line equation (since they both lie on it)
I.e.
For point (M,N), we have:
M=N/2 - 2/5
And for (M + P, N+4), we have:
M+P = (N+4)/2 -2/5
We substitute the value for M from our first equation into our second
equation:
(N/2 - 2/5) + P = (N+4)/2 -2/5
implies
N/2 - 2/5 + P = N/2 + 2 - 2/5
implies
P = 2
-Darren
"Fletch Bowling" <fletchb@gmail.com> wrote in message
news:2ee22479.0412012014.18091f09@posting.google.com...
> Hello,
>
> Trying to get back into school after many years away. I have to take
> an admitance exam which I am currently studying for. Here is a problem
> on a sample exam that is stumping me . I belive it is a y intercept
> problem Any ideas on how to solve? I am thinking you solve for y but
> that didn't seem to work for me.
>
> M and N are the X and Y coordinates, respectively, of a point in a
> coordinate plane. If the points (M,N) and (M + P, N +4) both lie on
> the line defined by the equation X = y/2 - 2/5, what is the value of
> P?
>
>
>
> Thanks, Fletch
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