Re: Help soving this problem?

From: Fletch Bowling (fletchb_at_gmail.com)
Date: 12/03/04 

Date: 2 Dec 2004 16:09:10 -0800

Hey thanks, your explanation made it easy to figure out. (athough I
still think the problem is way too hard for liberal arts admitance
test :)

Regards,
Fletch

"darrenn" <naylod-nospam@juno.com> wrote in message news:<O4OdnT138YTdBzPcRVn-3A@comcast.com>...
> So each point must solve the line equation (since they both lie on it)
>
> I.e.
>
> For point (M,N), we have:
> M=N/2 - 2/5
>
> And for (M + P, N+4), we have:
>
> M+P = (N+4)/2 -2/5
>
>
> We substitute the value for M from our first equation into our second
> equation:
>
> (N/2 - 2/5) + P = (N+4)/2 -2/5
> implies
> N/2 - 2/5 + P = N/2 + 2 - 2/5
> implies
> P = 2
>
> -Darren
>
>
>
>
>
>
> "Fletch Bowling" <fletchb@gmail.com> wrote in message
> news:2ee22479.0412012014.18091f09@posting.google.com...
> > Hello,
> >
> > Trying to get back into school after many years away. I have to take
> > an admitance exam which I am currently studying for. Here is a problem
> > on a sample exam that is stumping me . I belive it is a y intercept
> > problem Any ideas on how to solve? I am thinking you solve for y but
> > that didn't seem to work for me.
> >
> > M and N are the X and Y coordinates, respectively, of a point in a
> > coordinate plane. If the points (M,N) and (M + P, N +4) both lie on
> > the line defined by the equation X = y/2 - 2/5, what is the value of
> > P?
> >
> >
> >
> > Thanks, Fletch