Re: .99999... still=/= 1

From: S. Enterprize Company (smart1234_at_aol.com)
Date: 12/14/04


Date: 14 Dec 2004 10:06:47 GMT


>> From: smart1234@aol.com (S. Enterprize Company)
>> there must be something in the real number system that would explain
>> the time difference in these calculations that shows 1 = 1
>
>>From the fact that there are two different ways of computing a
>representation of the number 1, one of which is very fast and one of
>which is very slow, you conclude that the two results you get can't
>possibly be the same number, so there must be something in the real
>number system that makes 1 a different number from 1 depending on how
>it was calculated? On what principle of logic do you come to that
>conclusion?
>
>Or is your whole starting of this thread a lie? You admit that the
>periodic decimal fraction .99999... (using the real metric) and the
>integer 1 (using the usual embedding of integers in reals) are exactly
>the same real number, and the only thing different about the two
>representations of them is that it takes more work to figure out what
>real number is a particular periodic decimal fraction than it takes to
>figure out what real number is a particular integer, but assuming you
>do the work to figure out what each is, they turn out to be exactly the
>same real number?
>
>> Otherwise both computers would have shown 1 = 1 at the same time.
>
>So you believe it's impossible to write two different computer programs
>that produce the same result but one runs faster than the other and so
>it gets the answer faster than the other? So if one computer program
>takes longer than the other, you know for sure the results will be
>different?

   I am using a non-standard approach to something that seems to exist between
the cracks of real numbers. Like for example,

.999... < X < 1

  What is the space between .999... and 1 which we can call X, that prevents,
.999... from perfectly equaling 1. I did say .999... does converge to 1, but in
a series a convergence value never perfectly equals that value. It's just the
nearest thing that does.

  I approached this with the use of time or a dimensionless space that doesn't
allow it. The fact is there is no numbers between .999... and 1, but they are
right next to each other. I used two approaches to this, higher order
differential analysis which could analyze this in infinitesimal space DIM -->oo
between .999... and 1 or by the Gamma function which I used as a function of
time approaching infinity.

 Using the Gamma Function,

gamma(alpha) = INTEGRAL ( 0 to oo) (e^-t) * t^(alpha-1) dt

                   n-->oo
gamma ( 1 + 9/10^n) ~= 1

as 9/10^n converges to 1

   In each case, the more time you spend approaching 1, the closer you get to
1.

  Another example I used to show that there was an inequality of time with
equations, was by the example of the Distributive Property.

a ( b + c ) = ab + ac

  There is a difference in the amount of time needed to make the calculations
on the left and right side of the equal sign of this equation even thought they
are equal to each other. So I used a non-standard approach in showing that time
is a significant factor in the cracks of space between real numbers.

Smart's Alt. Physics News Group
http://pub39.bravenet.com/forum/show.php?usernum=3320272813&cpv=1
S. Enterprize (Science Journal)
http://smart1234.s-enterprize.com/



Relevant Pages

  • Re: Discrepancy in calculations with dollars and cents
    ... something to fudge the "equals" comparison. ... formula, might mitigate the problem. ... I do not recommend that option because it affects all calculations in ...
    (microsoft.public.excel)
  • Re: Proof 0.999... is not equal to one.
    ... trivial fsct and easy to prove! ... An infinite series, by definition, is a sequence. ... is a representation of a real number. ...
    (sci.math)
  • Re: Why 9.09 == 9.0899999999999999
    ... But debugging the code ... the watch window tells me d equals 9.0899999999999999. ... simple example consider ternary representation which uses the digits 0 1 2. ...
    (microsoft.public.vc.language)
  • Re: equality vs. identity in Conways "On Numbers and Games"
    ... >>If I use a representation in which each fraction has a unique ... >>identical because identity becomes the same as equality. ... >>representation involving unsimplified fractions of uniquely represented ... equals in arithmetic operations produces equal results. ...
    (sci.math)