Re: integrating (sin x)^(1/3)
From: A N Niel (anniel_at_nym.alias.net.invalid)
Date: 12/21/04
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Date: Tue, 21 Dec 2004 15:02:48 -0500
In article <nqrgs055v1q5iau7h3lv56s4fgm97oelef@4ax.com>, Tim923 <juggler923@verizon.net> wrote:
> Can someone remind me how this indefinite integral is solved?
Why do you think there is a nice formula for it?
Maple gave me this:
3/4*sin(x)^(4/3)*hypergeom([1/2, 2/3],[5/3],sin(x)^2)
Or, change variables t=sin(x) to get:
integral t^(1/3) dt/sqrt(1-t^2)
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