Re: abundance of irrationals

From: Jesse F. Hughes (jesse_at_phiwumbda.org)
Date: 01/17/05 

Date: Mon, 17 Jan 2005 17:59:58 +0100

mueckenh@rz.fh-augsburg.de writes:

> Jesse F. Hughes wrote:
>
>> Your "proof" (oh, I make myself chuckle so) cannot be a proof that
>> applies when R \ Q = {}, since it relies on the densities of Q and
>> R \ Q. If there are no irrationals, then it is not so that between
>> every two rationals is an irrational.
>
> You completely missed my reasoning.

I cannot argue with that.

Let me know if you have any more. I'll try to catch it next time. 

-- 
Jesse F. Hughes 
"How come there's still apes running around loose and there are
humans?  Why did some of them decide to evolve and some did not?  Did
they choose to stay as a monkey or what?" -Kans. Board of Ed member

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