Partitions of unity question
From: Tony (Ttiger222_at_hotmail.com)
Date: 01/31/05
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Date: Mon, 31 Jan 2005 17:24:01 -0500
If M is a topological space with the property that for every open cover X of
M, there exists a partition of unity subordinate to X, show that M is
paracompact.
I can't quite see how to do this. If {f_i} is a partition of unity for X =
{X_i}, then certainly
X = Union of {supp(f_i)} (over i), since if x is in M, then there exists a
function f_k such that f_k(x) is not zero since by definition of parition of
unity,
sum f_i(x) = 1 for all x in M (where the sum is taken over all i).
So if supp(f_i) was open for all i, then {supp(f_i)} would be a locally
finite refinement of {X_i} since supp(f_i) is a subset of X_i and the supp's
form a locally finite set.
But they may not be open. So I'm not sure what to do. For a particular k,
can I maybe write supp(f_k) as a union of a finite amount of open sets?
Because it seems clear to me that a finite refinement of a locally finite
set is locally finite. But it doesn't appear clear to me that any
refinement of a locally finite set is locally finite.
Any help is highly appreciated, Thank you,
Tony
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