how to interpret formula curvature

From: nlscb (nlscb_at_yahoo.com)
Date: 02/11/05


Date: 11 Feb 2005 12:52:58 -0800

I have a really nasty equation that I needed to use maple to determine
the curvature where the definition
of curvature is:

(dy^2/dx^2)/(1+(dy/dx)^2)^(3/2).

The final answer is REALLY nasty. I doubt that I could
solve for it's slope being zero w/o numerical methods.
It also never equals zero in the range that I am looking
at (0 to 100). It does have a maximum.

How do I interpret this? I went to wolfram.com, but
it doesn't really describe what you are supposed to do with
your results.



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