Re: A correction... I meant (x^2)^(1/2) = |x| not x^2^1/2 = |x|
From: Monty Hall (chickenkungpao_at_hotmail.com)
Date: 02/17/05
- Next message: robert j. kolker: "Re: Epistemology 201: The Science of Science"
- Previous message: robert j. kolker: "Re: Epistemology 201: The Science of Science"
- In reply to: William Elliot: "Re: x/x^3 simplification paranoia - found my answer VIVA WIKIPEDIA!"
- Next in thread: Stan Brown: "Re: x/x^3 simplification paranoia"
- Messages sorted by: [ date ] [ thread ]
Date: Thu, 17 Feb 2005 17:42:02 GMT
Sorry,
My precedence is not correct. To be sure, I meant (x^2)^(1/2) = |x|. I
have another question concerning the simplification of expressions
containing |x|, but I'll create another post.
Regards,
Monty
"William Elliot" <marsh@privacy.net> wrote in message
news:20050217091137.W29202@agora.rdrop.com...
> On Thu, 17 Feb 2005, Monty Hall wrote:
>
>> Found my answer in Wikipedia
>>
>> x^2^1/2 = |x|
>>
> Baloney. (x^2)^(1/2) = |x|
> By convention a^b^c is taken to mean a^(b^c)
> Thus x^2^(1/2) = x^sqr 2
> and x^2^1/2 is ambigious meaning possibly
> (x^2^1)/2 = (x^2)/2
>
- Next message: robert j. kolker: "Re: Epistemology 201: The Science of Science"
- Previous message: robert j. kolker: "Re: Epistemology 201: The Science of Science"
- In reply to: William Elliot: "Re: x/x^3 simplification paranoia - found my answer VIVA WIKIPEDIA!"
- Next in thread: Stan Brown: "Re: x/x^3 simplification paranoia"
- Messages sorted by: [ date ] [ thread ]
Relevant Pages
|
Loading
