Re: Sign conventions
From: Justin (no_at_spam.com)
Date: 02/21/05
- Next message: The World Wide Wade: "Re: Gabriel's Theorem - what I have learned thus far."
- Previous message: Alain Verghote: "" (2x-4)/ x - 5/(x+1) , an unorthodox method ?! ""
- In reply to: jstevh_at_msn.com: "Re: Sign conventions"
- Next in thread: Jim Spriggs: "Re: Sign conventions"
- Messages sorted by: [ date ] [ thread ]
Date: Mon, 21 Feb 2005 21:45:58 +0000 (UTC)
jstevh@msn.com wrote:
: The square root operator returns that number which when multipled times
: itself gives the square root argument e.g. sqrt(4) returns 2 and -2, as
: *both* multiply times themselves to give 4.
No. The square root *function* returns the nonnegative real number whose
square is the argument.
Idiotic rambling snipped.
Justin
- Next message: The World Wide Wade: "Re: Gabriel's Theorem - what I have learned thus far."
- Previous message: Alain Verghote: "" (2x-4)/ x - 5/(x+1) , an unorthodox method ?! ""
- In reply to: jstevh_at_msn.com: "Re: Sign conventions"
- Next in thread: Jim Spriggs: "Re: Sign conventions"
- Messages sorted by: [ date ] [ thread ]
Relevant Pages
|