Re: square root denominators
From: Oscar Lanzi III (ol3_at_webtv.net)
Date: 02/25/05
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Date: Thu, 24 Feb 2005 21:32:14 -0600
In some applications it is actually more profitable to rationalize the
NUMERATOR. Generally this involves variable expressions as opposed to
numbers. In another thread I describe a situation where I had to solve
by computer a quadratic equation of the form a^2 + bx + c = 0 with a
being potentially zero. Using a rationalized-numerator version of the
formula, c/(-b (+/-) sqrt(b^2-4ac)), allows one to avoid a zero or
near-zero denominator in such a case. Another example is integrating
sqrt((1+x)/(1-x)) dx by first rendering the integrand as
(1+x)/sqrt(1-x^2).
--OL
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