Counterexample: non-nilpotent formal power series with nilpotent coefficients
Hello, consider a comm. ring with 1, A. If a formal power series f\in
A[[X]] is nilpotent then its coefficients must be nilpotent. Now, what
about the converse? It appears that A cannot be Noetherian but does any
one have a counterexample for the converse?
Thanks.
Daniel Wolff
.
Relevant Pages
- consistent estimtators
... consistent. ... I'm looking for a counterexample to the converse. ... Prev by Date: ... (sci.math) - Re: Grey Squirrels
... >>In fact the converse. ... I suggest you keep your jackets on and desist from ... > rather than accept or constructively argue the points. ... Prev by Date: ... (uk.environment.conservation) - Re: Francis Ford Coppola Files Copyright Injunction Against Chris X !
... > Dogshit Danny wrote: ... > And what 'level' would you prefer to converse at considering the fact ... > that you seem to function at the emotional level of an infant? ... Prev by Date: ... (uk.politics.misc) - Re: Phones with louder than avearge output
... >Does anybody know of a phone that has a nice loud and clear output? ... BT Converse 225 or 425 ... Peter Parry. ... Prev by Date: ... (uk.telecom) - Re: OT: Joke thread
... Some computer scientists programmed a computer to be able to converse ... television shows, and local sports. ... When they enter an IQ of 70, it thought for a while and said "Okay. ... Prev by Date: ... (rec.gambling.poker) |
|