Re: e-permutation tensor
- From: tristan.buckmaster@xxxxxxxxx
- Date: 3 Apr 2005 06:29:54 -0700
> But I'm lost when we allow indieces to go to 4. How is an argument
of 4
> handled in a THIRD-order permuation tensor?
e^1 2 4 = -1
e^1 4 2 = 1
It is the same idea, where even swapping of the numbers = 1
odd swapping = -1
.
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- From: tristan . buckmaster
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