Re: p^2 = a^2+b^2+c^2
- From: Gerry Myerson <gerry@xxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Wed, 13 Apr 2005 13:33:13 +1000
In article <S6_6e.1633$5u4.6346@xxxxxxxxxxxxxx>, Don Reble <djr@xxxxx>
wrote:
> I observe, that for each (odd) prime P < 7000,
> if P == 1 mod 4, then P^2 has floor(P/8) representations
> as the sum of three positive squares;
> if P == 3 mod 4, then P^2 has ceil(P/8) representations.
>
> Is it true for all primes?
You may find what you need at
http://web.maths.unsw.edu.au/~mikeh/webpapers/paper63.pdf
--
Gerry Myerson (gerry@xxxxxxxxxxxxxxx) (i -> u for email)
.
- Follow-Ups:
- Re: p^2 = a^2+b^2+c^2
- From: Don Reble
- Re: p^2 = a^2+b^2+c^2
- References:
- p^2 = a^2+b^2+c^2
- From: Don Reble
- p^2 = a^2+b^2+c^2
- Prev by Date: Help with Symbols
- Next by Date: jordan homomorphism
- Previous by thread: p^2 = a^2+b^2+c^2
- Next by thread: Re: p^2 = a^2+b^2+c^2
- Index(es):
Relevant Pages
|
