Re: abundance of irrationals!)

richard@xxxxxxxxxxxxxxx (Richard Tobin) wrote in message news:<d3e1jn$2udj$1@xxxxxxxxxxxxxxxxxxxxxxx>...
> In article <fb701d3c.0504110456.5298f0df@xxxxxxxxxxxxxxxxxx>,
> W. Mueckenheim <mueckenh@xxxxxxxxxxxxxxxxx> wrote:
>
> >It talks about "ALL n" > n_0. Do you think "ALL n" supply a finite sum?
>
> Yes. For all n, the sum is finite, because all for all n, n is finite.

That's why I said that
SUM 1/2^k < 1
k e N

I is not important, how many of the terms 1/2^k may come along. W know
for sure that each of them is > 0, so that 1 - 1/2^k remains strictly
< 1.

Regards, WM
.