Re: Sum of factors
- From: Christian Bau <christian.bau@xxxxxxxxxxxxxxxxxxxx>
- Date: Tue, 19 Apr 2005 23:18:31 +0100
In article <d436pr$bmp$1@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
"Néstor" <c@xxxxx> wrote:
> Hi!
>
> Supose we have N<>M so that
>
> N=a*b
> M=c*d
>
> a<>b<>c<>d unknown, but:
>
> a+b = c+d
>
> Can we obtain a,b,c,d from N,M?
For every value of a, c is the solution of
(a + N/a) = c + M/c
or
c^2 - (a + N/a) * c + M = 0.
That is a simple quadratic equation which will have two solutions for
many values of a.
.
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