Re: Derivatives

From: "Boi" <boi@boi>
Date: Wed, 20 Apr 2005 13:01:30 +0200

> There is no need to use the chain rule for tis eqution i beleive you are
> right or very near right in your first guess.
>
> y= sin kx ---------------> dx= kcos kx
>
> y= cos kx ----------------> dx= - kcos kx
>
> ( I should remember this better ive been doing this exact stuff for the
> last
> 4 weeks at college) there is no need to use the chain rule ass this is
> used
> in functions of a function i.e. y= (2x^2)^4

Total nonsense, where does this k come from do you think? You just study
things by heart?
dx=k cos kx is not even correct, what you mean is dy=k cos kx dx. Ass.

.

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