Re: mathematics



Virgil wrote:
|For example, the intermediate value theorem, as I recall, is proved
|without actually coming up with all those intermediate values.

One needs to be a little careful here.

Suppose f is a continuous function on [0,1]
and f(0)<0<f(1). The greatest lower bound of
{x : 0<=x<=1 and f(x)>=0} is what I would call
an explicit example of a zero of f.

I hope the issue isn't with the term "all" here,
because it's somewhat unclear what it should mean
to "come up with" a set of reals that could be
pretty arbitrary (just a closed subset of (0,1)).

The intermediate value theorem is nonconstructive,
but for a different reason. One standard definition
of "real number" that works constructively too is
that it's an equivalence class of Cauchy-converging
sequences of rationals. In this case, we could take
for example the sequence a_n = i/n where i is the
smallest integer in 0,1,...,n such that for some
x<i/n one has f(x)>=0. This also is explicit. But
for a claim that an integer exists to be established
constructively, there must be a way in principle to
produce an example, and there's no such general way.

Nonconstructively, one says that such an integer
exists, and is explicitly given, because it's the
smallest integer having some property that 0 doesn't
have but n does have. If we assume that each integer
either has the property or does not have it, then
the existence of a smallest such integer follows by
mathematical induction. As usual, the culprit is the
law of excluded middle. One can't necessarily tell
whether f(x)>=0 holds somewhere on an interval; one
just assumes that in some abstract sense it either
does or does not.

A number of variations on the intermediate value theorem
hold constructively. The basic problem is with functions
that hover around near 0 in some subinterval. So one can
get values where the function is within an epsilon of 0.
One can also get an exact zero if for every subinterval
of [0,1] there's an N and a value of f whose absolute
value is >1/N on the subinterval. Obviously also given
some subinterval on which the function is zero, you can
get a zero!

Keith Ramsay

.



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