Re: Prove that a set is a monoid, but not a ring
- From: magidin@xxxxxxxxxxxxxxxxx (Arturo Magidin)
- Date: Mon, 25 Apr 2005 15:38:22 +0000 (UTC)
In article
<12255104.1114440699431.JavaMail.jakarta@xxxxxxxxxxxxxxxxxxxxxx>,
grimster <kelvarnsen1@xxxxxxxxxxx> wrote:
>ok, i did this as well. can anyone give me an example that shows that
>end n(k) is not a ring? an example that shows that distribuitivity
>fails...
To return lost context, you are trying to show that the polynomial
maps from k^n to k^n form a monoid under composition, but not a ring
(under, presumably, pointwise addition and composition).
So... Take n=1, let g(x) = x, h(x) = 1, and f(x) = x^2. You want to
show that f(g+h) is not equal to fg + fh. That should be trivial, at
least for k not of characteristic 2.
--
======================================================================
"It's not denial. I'm just very selective about
what I accept as reality."
--- Calvin ("Calvin and Hobbes")
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Arturo Magidin
magidin@xxxxxxxxxxxxxxxxx
.
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