Re: Differentiability at a point: understanding starting from set theory; request for help.



Adam,
You seem as confused as I was (sometimes I think I am even more confused
than before). I used a tutor whose website is at www.mathtutor1.com . This
guy is a college professor and explain things well. He does tutoring live
online, but believe it or not the equipment he uses makes it better than
meeting someone in person. I don't know if he still offers the first 30
minutes for free but he did for me and I bet if you ask he will do the same
for you.
Good luck,
Mkajuma
"A. Boom" <aboom@xxxxxxxxxx> wrote in message
news:Z_Wdnac-0bKbPfDfRVn-2Q@xxxxxxxxxxxxx
> Dear readers,
>
> I seek to understand a few ideas: derivatives at a point, if the domain
> is a subset of a finite set; the implicit assumptions in the following
> definitions.
>
> I acknowledge that my understanding is lacking and hence I am asking
> readers for assistance. I've been learning applied math and seek a more
> thorough understanding of these calculus ideas from a rigorous
perspective.
>
> I began with top definitions and then proceeded backwards to undercover
> what they rely on and what is meant. It seemed logical to do so.
>
> Ultimately, my goal is to understand the sequence of ideas leading from
> the axioms of set theory to the definition of a derivative at a point.
>
>
>
> 1) Definition. A function is differentiable at a if f'(a) exists. It is
> differentiable on an open interval (a,b) [or (a,infinity) or
> (-infinity,a) or (-infinity, infinity)] if it is differentiable at every
> number in the interval.
>
>
>
> So the above definition relies at the definition of what "f'(a) exists"
> means.
>
>
>
> 2) Definition. The derivative of a function f at a number a, denoted by
> f'(a), is
> f'(a) = lim_{h -> 0} (f(a+h) - f(a))/h
> if this limit exists.
>
>
>
> The above definition requires the definition of a limit.
>
>
>
> 3) Definition. Let f be a function defined on some open interval that
> contains the number a, except possibly at a itself. Then we say that the
> limit of f(x) as x approaches a is L, and we write
> lim_{x -> a} f(x) = L
> if for every number epsilon > 0 there is a corresponding number delta >
> 0 such that
> |f(x) - L| < epsilon whenever 0 < |x - a| < sigma.
>
>
>
> At last the fundamental definition is reached, or so it seems. However,
> the above definition relies on what "|f(x) - L|" means. It is to be the
> absolute difference between two numbers. Yet, that seems to imply that
> "|f(x) - L|" be meaningful for elements of the range of the function,
> and "|x - a|" be meaningful for the elements of the domain of the
> function. Is this always true? (I assume not). Is it implicitly assumed
> that numbers from the real set are being used for the domain and
> codomain since they have such properties?
>
> The above definitions are from the book titled Calculus: Single
> Variable, Early Transcendentals by Stewart.
>
> Definition 3) relies on, at least, the definition of a function, as well
> as the meaning of the magnitude function(?).
>
> (Note: I'm aware that some authors treat set relations before functions,
> however that order need not be followed, as taken from Proofs and
> Fundamentals: A first course in abstract mathematics by Bloch.)
>
>
>
> 4) Definition. Let A and B be sets. A function (also known as a map) f
> from A to B, denoted f: A -> B, is a subset F <= AxB such that for each
> a in A, there is one and only one pair of the form (a,b) in F. The set A
> is called the domain of the function and the set B is called the
> codomain of the function.
>
>
>
> The definition given above does not state requirements of the sets used
> as the domain and codomain of a function. As such, why does it seem to
> be assumed that the sets have the property of being ordered in the
> definition for derivatives. That is, where x > y or x < y or x = y,
> which is required for the use of "|f(x) - L".
>
> When elements of a set are listed, the order of listing is subject to
> the writers whim, and not dictated by the set, as far I know. A set can
> be shown to follow a relation such as given above.
>
> Why is it that when derivatives are discussed, even represented as
> graphs, the elements of the domain are ordered, when the elements of the
> set may be arranged so, but do not have such ordering? Like 1, 2, 3, 4,
> 5, and not 3, 5, 2, 1, 4.
>
> I read that the pioneers of differential calculus had as their main
> problem that of "instantaneous change", which was reasonably thought of
> as a real world problem. As such, the domain, being time, was
> necessarily ordered.
>
> Is the concept of a derivative not applicable to unordered sets?
>
> The last questions are the most difficult for me to clearly state, and
> perhaps that means they are silly; I don't know.
>
> Let A be a set where A = {1, 2, 3, 4, 5}. Let B be a set where B = {2,
> 4, 6, 8, 10}. Now let f: A -> B be a function with elements (1,2),
> (2,4), (3,6), (4,8), and (5,10). This function, when plotted, has an
> ordering and a simple graph. Does it have a derivative at any or all
> points of A? If not, why?
>
> Define a second function by g: A -> B with elements of g being (1,4),
> (2, 2), (3, 10), (4, 8), (5, 6). A plot of the graph does not have a
> "smooth" shape. Does this function have a derivative at any or all
> points in its domain? If not, why?
>
> Are derivatives not defined for arbitrary sets? Must the elements of the
> sets, themselves, be elements of sets such as the real numbers so that
> there is always a number between any two elements, even if such elements
> aren't in the domain of the function?
>
> I suppose that the last three paragraphs highlight what I don't
understand.
>
> Any and all constructive help is appreciated.
>
> Thank you for your time, Adam.


.



Relevant Pages

  • Re: Possible Calculus of Variations Problem
    ... of variations has nothing to say about this problem. ... calculus of variations has nothing to do with ... Dini derivatives. ... Shubert's Method, which works for a Lipschitz function on with ...
    (sci.math)
  • Re: 4=3 A maths joke
    ... which at least uses some basic calculus? ... the _calculation_ of derivatives. ... About "my hesitation" I, once again, don't have the faintest idea what ... of Leibniz's theorem for differentiation of an integral. ...
    (sci.math)
  • Mr. Mental Explains -Derivatives, Calculus and Other Simple Concepts
    ... Derivatives, Calculus and Other Simple Concepts ... represents the total number of people living in America while the Hero ... A dollar derives its value from something else. ...
    (rec.audio.opinion)
  • Re: schools banning homework
    ... When I was in a freshman in high school (grade 9) during the first ... I was able to crank out many derivatives and integrals in a somewhat ... A few weeks later I signed out a calculus textbook from the school ...
    (sci.research.careers)
  • Re: John Gabriels Theorem Revisited.
    ... posts I asked if the contributor would have been pleased had Gabriel ... Calculus & Concepts) is not a good book. ... It's about the average of the derivatives. ... becomes the average tangent gradient when the derivative is the slope ...
    (sci.math)