Re: JSH: Brainstorming over, for now





jstevh@xxxxxxx wrote:
Ok, I've finished brainstorming on the SFT and how to best present it.


Does that mean you won't be taking people up on their offers to connect you to the NSA? What do you think of people who have to, have to, HAVE TO!!!! talk with you, and when you finally turn to them to say, "OK, what do you want?", they say, "um, never mind"?

What do you imagine that tells us about your likelihood of getting
a hearing from them, ever?

It's clear you've never raised children, and equally clear that
you've never gotten past that stage of your own childhood.

It's been a VERY useful few days as most importantly I've managed to
air out my paranoia about the dangers of this research, and communicate
loud and clear I hope, so that the people who are supposed to pay
attention to problem areas assuredly noticed!


What does that mean? All you did was to throw a tantrum.

Which makes me feel a little silly for being worried--as nothing has
happened--but then again, how do you know if you don't check?


Most people don't assume that their every waking thought is the most brilliant event since the time of Archimedes. It was your own inability to engage in any sort of realistic self-evaluation that led to this exercise in vanity.

You have had more feedback, more useful feedback, and more pertinent
feedback, than any five people I know. If you had the intelligence you
claim, and weren't a self-absorbed cretin, you would have known that
you didn't need to be freaking out. You consistently ignore the signs.

Just recall what came of your alleged "critique" exercise. Ostensibly
a declaration of honest self-evaluation, it rapidly degenerated into
your own self-promotion. You requested a proof that one could prove
that an algebraic number could be expressed as the quotient of two
coprime algebraic integers. You were *so* certain that it was an
underlying assumption, despite a long history of having your baby
version of mathematics shown to have been just that.

Here's the article from Google:

	From: jst...@xxxxxxx
	Newsgroups: sci.math
	Subject: Re: JSH: Critique means slow, and thorough
	Date: 29 Mar 2005 15:46:11 -0800
	Organization: http://groups.google.com
	Lines: 144
	Message-ID:
              <1112139971.010172.257450@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>


W. Dale Hall wrote: > jst...@xxxxxxx wrote:

		<deleted>

	> >
	> > If so, then that means that you might have an algebraic
	> > number x/y where x and y are members of that ring, but
	> > not algebraic integers.
	> >
	> > So consider what follows from the ring of algebraic numbers,
	> > which is also a field, as every algebraic number can be
	> > written as a ratio of coprime algebraic integers so I can
	> > show what happens in detail, so in algebraic numbers I can 	
	> > have
	> >
	> > 	a/b
	> >
	> > where a and b are algebraic integers, so you have
	> >
	> > a/b = x/y
	> >
	> > where in the ring where x and y are members, you may also
	> > have
	> >
	> > cx/cy = a/b
	> >
	> > where cx and cy are algebraic integers, while x and y are
	> > not algebraic integers.
	> >
	> > Then coprimeness in the ring of algebraic integers does not
	> > mean coprimeness in the more inclusive ring.
	>
	> This is incorrect. If R and R' are commutative rings with
	> identity, R a subring of R', then whenever elements r,s of R
	> are coprime in R, then they are coprime in R'.
	>
	> >
	> > But if you don't realize that possibility, and worse, assume 	> >
that you've included all rings where the two key properties
	> > hold, you can have an odd thing, where you can prove
	> > "coprimeness" by relying on coprimeness in the ring of
	> > algebraic integers, and algebraically find that two numbers
	> > are not coprime, and thus have the appearance of proving two
	> > different and opposite things.
	> >
	>
	> Can't happen.  Here's why.
	>
	> Let r,s be coprime in R. That means there are u and v in R
	> such that
	>
	> 		ur + vs = 1.
	>
	> Now, r,s and u,v are in R. R is a subring of R'. Thus, r,s and
	> u,v are elements of R'. The operations of R extend to
 	> operations of R', so the equation
	>
	> 		ur + vs = 1
	>
	> also holds in R'. Thus, r and s are coprime in R'.
	>

	That's correct, but can you now prove that for every case

		a/b

	where a is an algebraic integer and b is an algebraic integer,
	and a is coprime to b that you can find a construction

		ax + by = 1

	where x and y are algebraic integers?

	If so I'd think that'd be a powerful argument against my claims.

	Why don't you try?
	******************

Note the request? Just so I didn't cheat, you made sure to be explicit:

	So that there's less confusion, assume you start with a/b being
	the root of a non-monic polynomial irreducible over Q, as if a/b
	is rational that's trivial to handle.

	Now, given an algebraic number a/b that is the root of a non-
	monic polynomial irreducible over Q, can you prove that you can
	find x and y such that

		ax + by = 1?

	> > A simple analogy that I've given before is to consider 6 and
	> > 2 in the ring of evens.
	> >
	>
	> Bogus example: no identity element.
	>

	Not really, as in fact, that's essentially what happens with the
	ring of algebraic integers where people *assume* that given a
	and b coprime algebraic integers that you can always find

		ax + by = 1

	where x and y are algebraic integers, but that is never proven.
                                                  ********************
Note your claim?

	It's a BFC, where by assuming that coprimeness in algebraic
	integers proves global coprimeness, people assume that you can
	find x and y above.

	It's a circular position, or can you prove otherwise?

Can't leave it alone, can you?  Gotta get that dig in: mathematicians
only assume, they never prove.

	I think that you may *believe* you can prove that without ever
	having seeing a proof and now with the challenge you can see
	that, or you can show I'm wrong.

	If I'm wrong here, then I really have to reconsider quite a few
	things.


James Harris

Now, let's recall what happened:

	1. I responded with a proof of exactly what you claimed was
	   never proven.

	2. You choked, claiming, among other things:

		My point is that the "field of rationals" is in
		fact, not a field, as that's a misnomer.

		My point is that mathematically, there's no way to
		block convergent infinite sums, so what happens is
		by *saying* they are blocked, you step into a non-
		math area, which falls apart if you do anything
		that depends on your arbitrary choice.

		Now this issue has come up before, where I've noted
		that even doing something as simple as adjoining 1/2
		to the ring of integers will give you reals.

	3. You then decided that what you had to do was *stop* the
	   critique of your own work, and critique Dedekind, instead:

		Well for the question about when the problem entered
		into the field of mathematics, that's when, and I
		guess I didn't figure on Dedekind having made the
		mistake, but I guess I should have.

		The proof of a problem with the current understanding
		of the ring of algebraic integers, which if certain
		sci.math posters are right, refutes a famous claim by
		Dedekind, which forms the basis for the theory of
		ideals, so basically, I've shot down the theory of
		ideals.

		Now I'm fairly confident that there has to be a mistake
		in Dedekind's work as I've faced a mystery for a while
		now, which is the fervent nature of defense of certain
		odd positions.

What do we have, then?  When faced with clear evidence of your failure
to understand some elementary mathematics, you decide that you don't
really need to go any further into that self-examination thing. No, it's
much more likely that a person whose work has been virtually *raked over
the coals* for over a hundred years, who must have goofed. Not you. It's
never you who has missed some fine (or not-so-fine) point.

	JSH momentary whim trumps a century of dedicated research.

Does the absurdity of this fail to strike you?

My fears about working on the factoring problem go back for YEARS and
have affected a lot of things for me, so it's a tremendous relief to be
here now with what I feel is a major result, and it looks like
everything is fine.

No worries.

Oh, so there's no need to go to the NSA? How do you interpret this? You're right (because that's the definition of right), factorization can be done by infants using ordinary household materials, but we're really save, and the NSA doesn't need to get in on the game?

Do those two things fit together at all?


Things get a lot more boring from here for the rest of you, as there's less need for me to talk anything out, as I think I've learned what I needed to know, and a lot less interest on my part in this subject area anyway, as I'm getting that been there done that feeling.

Extreme mathematics is about the extreme--pushing limits and the
envelope.


I would have imagined a flimsier sort of paper is what's getting pushed. The kind that comes on a squat cylindrical roll, and is perforated at regular intervals of about 4 inches. At the end of the process, I'm thinking a little chromium lever gets pressed.

Maybe I burned myself out ahead of time on factoring, worrying about it
so much, but now it just seems like so much old hat.


Here I sit, broken hearted ...

Of course, papers to be sent off, but I have a backlog now.  I've been
sitting on papers versus working them out to be sent off, as it's all
just kind of tedious and annoying--the social crap.


I told you there might be crap involved. That and some sort of paper.

In any event, the world is still here.  The economy didn't crash, and
I'm feeling stupid but giddy.

Sometimes fears are just uncalled for, and unnecessary, but you have
them anyway.


There's always a moral to the story. I'm impressed by your ability to reach into that bag and always pull out the one that shows how you're a thoughtful, if clueless, person.

I suppose if one views the moral as the philosophical equivalent of
being tucked into ones bed by mommy, then a comfy-cozy moral is as
good as any.



James Harris


Dale .



Relevant Pages

  • Re: JSH: The "Published" paper he dosent what you to know about.
    ... I'm not sure what he wants from his "object ring", ... so the other factors needed to be coprime to f --- in the ring ... happen in the ring of algebraic integers. ... Dedekind's work and the theory of ideals. ...
    (sci.math)
  • Re: Attacking my algebraic integer work
    ... > The paper Advanced Polynomial Factorization has been retired. ... >> his arithmetic in the ring of algebraic integers. ... not coprime to 5 in some yet-to-be-well-defined ring of objects, ...
    (sci.math)
  • Re: JSH: The "Published" paper he dosent what you to know about.
    ... are algebraic integers. ... You however infer that one of the roots IS coprime ... And since you are saying that Galois theory is ... you must be saying that it is wrong in the ring ...
    (sci.math)
  • Re: JSH: The "Published" paper he dosent what you to know about.
    ... -if a and b are coprime they remain coprime in any ... ring that contains the algebraic integers. ... the algebraic integers are not like the evens. ... I expect it's a mistake to assume that James knows what mathematicians mean ...
    (sci.math)
  • Re: New paper, algebraic integers, Galois Theory
    ... you agree that the numbers a_i and 5 are not coprime in the ring ... of algebraic integers, contrary to the claim of your paper. ... > monic polynomials with integer coefficients. ... you make some sort of contradiction. ...
    (sci.math)