Re: An interesting problem of algebra
- From: TLOlczyk <olczyk2002@xxxxxxxxx>
- Date: Thu, 05 May 2005 10:50:07 GMT
On Thu, 05 May 2005 06:10:41 EDT, tunnel <tunnel2001@xxxxxxx> wrote:
>For A ,B is matrix.(AB)^3=BA . proof that AB=BA
Huh.Isn't this obvious?
(AB)^3=(A^3)(B^3)= B^3 A^3 =BA
so
B^2 A^2 =1
but
(AB)^3=A^2B^2 AB =B^2 A^2 AB=AB
so
BA=(AB)^3=AB
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Thaddeus L. Olczyk, PhD
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.
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