Re: An interesting problem of algebra
- From: Robin Chapman <rjc@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Thu, 05 May 2005 12:25:17 +0100
TLOlczyk wrote:
> On Thu, 05 May 2005 06:10:41 EDT, tunnel <tunnel2001@xxxxxxx> wrote:
>
>>For A ,B is matrix.(AB)^3=BA . proof that AB=BA
> Huh.Isn't this obvious?
No.
> (AB)^3=(A^3)(B^3)
You might like to calculate both sides for
A = (1 1)
(0 1)
and
B = (1 0)
(1 1).
> Thaddeus L. Olczyk, PhD
Robin J. Chapman, MA PhD NBG ASBO
--
Robin Chapman, www.maths.ex.ac.uk/~rjc/rjc.html
"Elegance is an algorithm"
Iain M. Banks, _The Algebraist_
.
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