Re: proof help
- From: "vsgdp" <spam@xxxxxxxx>
- Date: Thu, 5 May 2005 13:44:03 -0700
> Of course there is a quick advanced way: use Mean Value Theorem.
Okay I think that helps, is this what you had in mind for using the MVT:
Let f(x) = cos(x)
By the MVT, there exists an x0 s.t.
f'(x0) = [f(b) - f(a)] / (b-a) for any [a, b] contained in R.
Then since |f'(x)| <= 1, we have
| [f(b) - f(a)] / (b-a) | <= 1.
==>
| f(b) - f(a) | <= |b - a|
.
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- From: Zdislav V. Kovarik
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