Re: Convergence of Newton's method for finding a root of a polynomial

Carlos Moreno <moreno_at_mochima_dot_com@xxxxxx> wrote:

> It's quite obvious that it can not be true. The case where P'(x) = 0
> clearly makes it fail, right? Well, there will always be one starting
> point such that the first iteration will take x to the exact point
> where P'(x) = 0.

Suppose P(x) = x^2 - 1

Then P'(x) = 2x

What is the starting point such that the first iteration will take x to
the exact point where P'(x) = 0?
--
Daniel W. Johnson
panoptes@xxxxxxxxxx
http://members.iquest.net/~panoptes/
039 53 36 N / 086 11 55 W
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