Re: Aut H / Inn H



Li Yi top-posted yet again:

> It is clear that
> sigma_i = sigma_{-i}
> sigma_j = sigma_{-j}
> sigma_k = sigma_{-k},
> right?

Yes.

> But I find
> sigma_i(i) = i i (-i) = -i

Funny i^2(-i) = -(-i) = i :-(

--
Robin Chapman, www.maths.ex.ac.uk/~rjc/rjc.html
"Elegance is an algorithm"
Iain M. Banks, _The Algebraist_
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