Re: Problems I have with 1.999...=2

In article <mWzhe.4431$x85.1820@trnddc01>,
Kirby Cook <kwmcook@xxxxxxxxxxx> wrote:

>> That is true. 1 is not a member of the set { .9, .99, .999, ... }.

>Since the preceding post could only be described as inattentive, I was
>going to ignore it. But I won't, after all.
>My point, which I consider sufficient, is that .999... is a member of
>the described set, and 1 isn't.

..999... is not a member of the set { .9, .99, .999, ... }. The set consists
of the numbers 1-10^-n for n=1, 2, ... If you disagree, you will no doubt
be able to tell me which value of n has 1-10^-n = .999...

-- Richard


.

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