Re: prove it measurable
- From: José Carlos Santos <jcsantos@xxxxxxxx>
- Date: Thu, 19 May 2005 22:41:38 +0100
A N Niel wrote:
He said R^n, now you say [n,n+1], a bit confusing perhaps...
Oops, quite right. I did not notice that. Of course, the method that I described also applies to R^n.
Best regards,
Jose Carlos Santos .
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