Re: existence of solution to x = f(x) = g(x) ?
- From: alain verghote <alainverghote@xxxxxxxx>
- Date: Sun, 22 May 2005 05:28:29 EDT
Dear Gary,
Whenever possible I prefer dealing 'constructively'
with problems.
The power 'approach since m^[0](u)= u seems more
direct and meaningful ,but you are right "there could
be so many diifferent ways... " .
NOTICE:
1°)x= f(x)= g(x) => (f(x)-g(x))=0
fixed points xi belong to { roots of (f-g) },
2°)have a look at cases f(x)=m^[a](x),g(x)=m^[b](x)
a ,b # 0 and a-b # 0 ,
like f(x)=2x+1 , g(x)=4x+3 or (2x+1)^[2]
f(x)=sin(3x) ,g(x)=sin(3*sin(3x)) ...
Bon courage,
Alain.
.
- References:
- existence of solution to x = f(x) = g(x) ?
- From: \"Gary Z.\"
- existence of solution to x = f(x) = g(x) ?
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