Re: cl(bigcap_{1<=q<=infty} L^q) = L^p

From: "Martin" <sleziak@xxxxxxxxxxxxx>
Date: 26 May 2005 06:56:28 -0700

If we denote by Cc(R) all continuous functions with compact support,
then the set Cc(X) is dense subset of L^p. (Rudin: Real and Complex
Analysis, Theorem 3.14)
Since Cc(X) belongs to each L^p, we arrive to your conclusion - this is
another possibility for the proof.
Martin

.

Follow-Ups:
- Re: cl(bigcap_{1<=q<=infty} L^q) = L^p
  - From: David C . Ullrich
- Re: cl(bigcap_{1<=q<=infty} L^q) = L^p
  - From: Kira Yamato

References:
- cl(bigcap_{1<=q<=infty} L^q) = L^p
  - From: Kira Yamato

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