Re: Help (polynomial)



big.ass wrote:
>
> I see no advantage. It seems too laborious too.

You could be right, but I may try pursuing it
a bit further.

> Terms in x^3 are still there. If you make a
> substitution (with Mathematica for example)
> you get:
> 1 - ((4 u + u^2*(3 + w)x - x^2))(u^2*(-1 + v) + x^2)

I'm not sure why you switched everything round,
but in the first quadratic the x should multiply
4u not u^2.(3 + w), and one or two signs in that
bracket don't look right either.

.

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