Re: CANTOR's theorem
- From: mueckenh@xxxxxxxxxxxxxxxxx
- Date: 4 Jun 2005 06:35:45 -0700
Virgil wrote:
> > > > > > map
> > > > > > 1 --> {1}
> > > > > > 2 --> {1,2}
> > > > > > 3 --> {1,2,3}
> > > > > > ...
> > > > > > n --> {1,2,3,...,n}
> > > > > > ...
> > > > > >
? --> {1,2,3,...}
> >
> > > I see no conflict between these two. Why N should be in the image escapes
> > > me.
> >
> > Because it is a one-to-one mapping. And the whole set N is on the left
> > hand side and on the right hand side.
>
> Where? I do not see it on either side.
>
> The members of N are on the left, and some proper subsets, often callled
> "initial subsets", of N are on the right, but where is N?
It had been snipped erroneously. Now you can see it.
Regards, WM
.
- Follow-Ups:
- Re: CANTOR's theorem
- From: Virgil
- Re: CANTOR's theorem
- From: Robert Kolker
- Re: CANTOR's theorem
- References:
- Re: CANTOR's theorem
- From: mueckenh
- Re: CANTOR's theorem
- From: *** T. Winter
- Re: CANTOR's theorem
- From: mueckenh
- Re: CANTOR's theorem
- From: Virgil
- Re: CANTOR's theorem
- Prev by Date: Re: Cantor and the binary tree
- Next by Date: Re: A graph theory problem
- Previous by thread: Re: CANTOR's theorem
- Next by thread: Re: CANTOR's theorem
- Index(es):