Re: Cantor and the binary tree



In article <MPG.1d0fd70a2aca34399896a7@xxxxxxxxxxxxxxxxxxxxxxxxx>,
Tony Orlow <aeo6@xxxxxxxxxxx> wrote:

> In article <ITSnetNOTcom#virgil-7F6FBB.13541107062005
> @comcast.dca.giganews.com>, ITSnetNOTcom#virgil@xxxxxxxxxxx says...
> > In article <1118166450.883263.12840@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
> > mueckenh@xxxxxxxxxxxxxxxxx wrote:
> >
> > > Virgil wrote:
> > > > In article <1118049962.009645.111100@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
> > > > mueckenh@xxxxxxxxxxxxxxxxx wrote:
> > > >
> > > > > Daniel W. Johnson wrote:
> > > > > > <mueckenh@xxxxxxxxxxxxxxxxx> wrote:
> > > > > >
> > > > > > > You have shown that set theory is inconsistent. Congratulations.
> > > > > >
> > > > > > No.
> > > > > >
> > > > > > He has shown that the combination of set theory with your
> > > > > > assertions is
> > > > > > inconsistent.
> > > > >
> > > > > The basic element of the binary tree is the branching where a path is
> > > > > separated.
> > > > > /
> > > > > B
> > > > > /\
> > > > > If set theory cannot describe this fact then it is useless.
> > > >
> > > > And if this path separation cannot do contour integration is it equally
> > > > useless? Set theory is not obligated to analyse binary trees.
> > >
> > > Does it forbid my way of analysing the tree?
> >
> > Only logic is needed to do that. In a maximal binary tree, every maximal
> > path can only be "separated" from ALL other paths by the set of ALL
> > nodes that it passes through (except for the root node which is common
> > to all) so the set of paths associates with a set of infinite subsets of
> > the set of nodes.
> >
> And yet, one can say each node in the tree is identified by the infinite
> set of unique paths which pass through it, so by that logic, there are
> infinitely many more nodes than paths. That chain of thought doesn't
> work.

Actually, any node is uniquely identified by any pair of paths which
split at that node, so on that argument the number of nodes cannot
exceed half the number of paths.
.



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