Re: field extension problem



Li Yi wrote:

> Well, I know
> [F(a) : F] = m
> and
> [F(b) : F] = n.
>
> But I think I need
> [F(a)(b) : F(a)] = n
> in order to apply [F(a,b):F] = [F(a,b):F(a)][F(a):F]

(i) what do you think |F(a,b):F| should be?

(ii) can you prove it?

--
Robin Chapman, www.maths.ex.ac.uk/~rjc/rjc.html
"Elegance is an algorithm"
Iain M. Banks, _The Algebraist_
.



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