Re: the Reals really have negative curvature built-in and negative-Reals are superfluous



> From: a_plutonium@xxxxxxxxxxx
> But it is terribly difficult to see that Reals are negative curvature
> of Lobachevskian geometry.

It's my understanding that the definition of "curvature" as applied to
a metric space, which distinguish Euclidean (flat) spaces from
hyperbolic etc. spaces, applies only to 2-dimensional spaces and by
extension to multi-dimensional. It doesn't apply to 1-dimensional
spaces, so what you say there seems to be meaningless. If you have a
meaning to the word "curvature" which applies to 1-dimensional spaces
such as the reals, please tell us that definition or post a link to an
online definition.
.



Relevant Pages


Quantcast