Re: difficult system of equation
- From: Dollar Stéphane <DF1234541RK8202@xxxxxxxxxxxx>
- Date: Wed, 06 Jul 2005 22:03:02 +0200
leonid.uk@xxxxxxxxx a écrit :
How to find a real number solution of the system 4*x*y+y^2+2*z^2=-3, 4*x*z+x^2+2*z^2=1, 8*x*z+y^2+2*z^2=1
Thanks
Hi,
You make L1-2*L2+L3
you obtain an equation in x and y
It is 2° degree ... .
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