difficult system of equation
- From: leonid.uk@xxxxxxxxx
- Date: 6 Jul 2005 12:51:28 -0700
How to find a real number solution of the system
4*x*y+y^2+2*z^2=-3,
4*x*z+x^2+2*z^2=1,
8*x*z+y^2+2*z^2=1
Thanks
.
- Follow-Ups:
- Re: difficult system of equation
- From: Dollar Stéphane
- Re: difficult system of equation
- Prev by Date: Re: Relative Cardinality
- Next by Date: Re: Relative Cardinality
- Previous by thread: Generalization of the 10 digit problem
- Next by thread: Re: difficult system of equation
- Index(es):
Loading
