Re: Trisecting an arbitrary angle

>
> "bassam king karzeddin" <bassam@xxxxxxxxxx> schrieb
> im Newsbeitrag
> news:29354512.1121766911405.JavaMail.jakarta@nitrogen.
> mathforum.org...
> > That is grate,
> >
> > This,might open doors to constructible polygons
> >
> > In fact,I have deduced & proved the same thing,I
> have mentioned that here:
> >
> >
> http://mathforum.org/kb/message.jspa?messageID=3802920
> &tstart=0
> >
> > I will provide examples soon.
>
> If I understand correctly, you have shown that in an
> triangle with
> the sides a^3 , a*(b^2-a^2) , b*(b^2-2*a^2) one angle
> is three times
> another one.
>
> The more interesting question would be: given an
> angle, how to
> construct a triangle with the sides a^3 , a*(b^2-a^2)
> , b*(b^2-2*a^2)
> and the given angle?
>
> Jutta
>

Take a finite straight line with two ends (A & B)
Draw an arbitrary angle from one end A & draw its triple from other end B,and wherever intersection of the two Angeles lines occur call it point C

Then,YOU have the triangle.
.

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