Re: Cone in a groove
- From: "Narasimham" <mathma18@xxxxxxxxxxx>
- Date: 24 Jul 2005 09:32:29 -0700
matt271829-news@xxxxxxxxxxx wrote:
> Narasimham wrote:
> > Let the angle sought between cone axis and V-groove line be th.
> > Consider the tangent plane inclined at angle V/2 to horizontal
> > plane.
>
> The way the problem is worded, the tangent planes are inclined at an
> angle V/2 to the VERTICAL plane. That's how I understood it anyway.
> (However, this obviously won't matter if you've just rotated the whole
> figure.)
>
> > Draw 3D diagram so that tan(V/2) = h/w where h is altitude normal
> > to plane of symmetry and w is width of the right angled triangle as an
> > extruded prism. At angle th, we have tan(C/2)= h/(w/sin(th)), or
> > sin(th) = tan(C/2)/tan(V/2), the needed result.
>
> I don't agree with your answer, but unfortunately I don't understand
> your explanation so I can't show what is wrong with it (assuming there
> IS something wrong with it).
Yes ,this error is corrected and posted separately.
.
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