Re: Self Study problem help - Group theory

In article <08jbe1psbcrpvldkfkjggvmkvig661mcvh@xxxxxxx>,
quasi <quasi@xxxxxxxx> wrote:

> On 25 Jul 2005 19:38:26 -0700, abe.buckingham@xxxxxxxxx wrote:
>
> >Unfortunately I do not understand what you mean when you say that 'k^m
> >is not germaine' and cannot seem to find a definition for germaine.
>
> Germaine is an older form of German, hardly used any more.

Sorry, I meant "germane." http://www.thefreedictionary.com/germane

--
Gerry Myerson (gerry@xxxxxxxxxxxxxxx) (i -> u for email)
.

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