Re: Self Study problem help - Group theory

I see what you mean about 1/9. Perhaps it would be better to simple
define X to be all rationals in lowest terms with an odd denominator? I
suspect that it would still work this way.

I have convinced myself that if a, b, c, and d, integers with b and d
odd then (a/b) + (c/d) in lowest terms is odd so I am content that I
had that portion correct.

Unfortunately I do not understand what you mean when you say that 'k^m
is not germaine' and cannot seem to find a definition for germaine.
With the revision to the definition of X to include all odd
denominators could I simply take an odd prime p not in the denominator
of k and say that 1/p is not constructed therefore k cannot generate
the group, and therefore X is not cyclic?

Thanks again for all the help, I'm glad to see I was on the right track
but also glad to see that I was correct about being a bit off the mark.
Sometimes it's hard to tell if I'm completely off my rocker when I'm
studying alone.

.

Relevant Pages